There are three consecutive even integers. If twice the first integer added to the second is 268,244, find all three integers.

Answer 1

x, x+2, x+3

2x+x+2 = 268,244

3x = 268,242

x = 89,4,14

x+2 = 89,416

x+4 = 89,418

sum of twice the first (2)(89,414) + second (89,416) = 178,828 + 89,416 = 268,244