One number is eight less than twice the other. Their sum is 100. find the number

Answer 1

Set up a system of equations:

x = 2y - 8

x + y = 100

Substitute x in terms of y from the first equation into the second equation and solve for y:

x + y = 100

(2y - 8) + y = 100

3y - 8 = 100

3y = 108

y = 108 / 3 = 36

Plug in the value for y into the first equation to solve for x:

x = 2y - 8 = 2(36) - 8 = 64

The number = 64 and the other number = 36

Answer 2

x=2y-8

x+y=100

2y-8+y=100

3y = 100+8

y=108/3 = 36

x=2(36)-8 = 72-8= 64

the two numbers are 64 and 36, which sum to 100

64= 36(2)-8 = 72-8 = 64