P = 2(l + w)
P/2 = l + w
l = 2w + 10
P/2 = 2w + 10 + w
P/2 = 3w + 10
170/2 = 3w + 10
85 = 3w + 10
3w = 75
w = 25
l = 2(25) + q0
l = 50 + 10
l = 60
A = 60(25) = 1500 ft2
Jason T.
asked 09/29/20jim is enclosing a rectangular garden with 170 feet of fencing. the length of thr garden is 10 feet more than twice its width, w. determine the area of the garden, in square feet. use an algebraic approach to model the problem.
P = 2(l + w)
P/2 = l + w
l = 2w + 10
P/2 = 2w + 10 + w
P/2 = 3w + 10
170/2 = 3w + 10
85 = 3w + 10
3w = 75
w = 25
l = 2(25) + q0
l = 50 + 10
l = 60
A = 60(25) = 1500 ft2
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