**Question**: A yard has a perimeter of 216feet. If 10times the length of the yard equals 17 times the width, what are its dimensions

**Equation**: 216 feet = 2l + 2w

*In order to solve you'll need one variable. Therefore, solve for either length or width so that the equation can be rewritten with one variable. *

10l = 17w

l = 17/10w

*Now, rewrite the equation 216 = 2(17/10w) + 2w*

216 = (34/10)w + 2w

216 = (34/10)w + (20/10)w

216 = (54/10)w

(216)/(54/10) = w

2160/54 = w

*Simplify w and plug it in for w to solve for the length when the perimeter is 216 yards.*

216 = 2(l) + 2(w)

216 = 2l + 2(40)

216 - 80 = 2l

136 = 2l

68 = l

**Answer**: Therefore, the dimensions of the yard are 68 by 40.