Find three consecutive positive integers such that the product of the first and the third minus the second is one more than 10 times the third.

Question

-Please solve step by step I need HELP!!

ASAP TOO!

Answer 1

x = first

x+1 = second

x+2 = third

x*(x+2) - (x+1) = 10(x+2) + 1

x^2 + 2x -x -1 = 10x + 20 + 1

x^2 + x - 1 = 10x + 21

x^2 - 9x - 22 = 0

(x-11)(x+2) = 0

x = 11 or x = -2

since integer positive, x = 11 is only valid solution

integers are 11,12,13