what is the standard form of the equation of the line passing through the point (2, 5) and perpendicular to the line 4x-y=2

Question

what is the standard form of the equation of the line passing through the point (2, 5) and perpendicular to the line 4x -y =2

Answer 1

the given equation, 4x-y=2 rewritten as y=4x-2 has slope m=4, the coefficient of the x term

the line perpendicular has slope of negative the inverse of 4, or -1/4

y-h=m(x-k) where m=-1/4 and (k,h) = (2,5) giving

y-5=(-1/4)(x-2) or

4y-20 = -x+2 or

x+4y=22 or