Find a general form of an equation of the line through the point A that satisfies the given condition. A(10, -1); perpendicular to the line x - 9y = 3

Question

 Can you please explain how to solve this problem? It also has to be written in standard form.

Answer 1

Lets transform  x-9y = 3 into y = mx+b form

 

-9y = -x+3

 y = (1/9)x-(1/3)

 

Plug in the x and y value of point A.

 

-1 = -9(10)+b   (perpendicular functions have negative reciprocal slopes)

-1 = -90+b

89 = b

 

Your equation is  y=-9x+89

 

In the general form,

 

9x+y = 89