Three consecutive even integers are such that three times the least decreased by twice the sum of the greater two results in 2.

Answer 1

Consecutive even integers (or odd integers for that matter) will increase by two's.

So if

x = first consecutive even integer

then

x + 2 = second consecutive even integer

x + 4 = third consecutive even integer

So what we will do is take the description of the above situation and translate it into an equation which we will solve for x.

The least even number is x. The greater two are x+2 and x +4

If three times the least decreased by twice the sum of the greater two results in 2, that means:

3x - 2(x+2 + x+4) = 2 which we can solve for x.

That gives us the least number. Then we can find the other two by calculating x+2 and x+4

3x - 2(x+2 + x+4) = 2 combine like terms

3x -2(2x +6) =2 then distribute

3x -4x -12 = 2 combine like terms

-x - 12 = 2 then add 12 to both sides

-x = 14 then multiply by -1

x= -14

So the least even integer being asked for is -14. The other two are -12 and -10

Answer 2

they are X, X+2, X+4

THree times the smallest SUBTRACT 2 times the largest has a difference of two:

3x - 2(x+4) = 2

3x - 2x - 8 = 2

x - 8 = 2

x = 10

10, 12, 14

3(10) - 2(14) = 30 - 28 = 2