Write the equation of a line that passes through point (8,-6) and (0,6)

Answer 1

Answer 2

Use the two-point form:

(y + 6) / (x - 8) = (-6 - 6) / (8 - 0)

(y + 6) / (x - 8) = -12 / 8

(y + 6) / (x - 8) = -1.5

y + 6 = -1.5x + 12

y = -1.5x + 6

Answer 3

You will need to find the equation of the line in slope intercept form y=mx+b.

First, find the slope m using slope formula m = (y_2-y_1)/(x_2-x_1) which is m=(6-(-6))/(0-8)=-12/8=-3/2

Now that you found the slope, your equation intercept form looks like y=-3/2 x+b.

Both points (8, -6) and (0.6) belong to this line, therefore both points coordinates satisfy line above which means: 6=-3/2(0)+b (i used second point here)

Solving for b we will get y intercept which is b=6

Finally, the line that passes through points (8,-6) and (0,6) has equation: y=-3/2 x + 6