Write the first 4 terms of the sequence

Question

f(n)=32(1.5)n

what are the first 4 terms of this sequence?

Answer 1

f(n)=32(1.5)n

First simplify you sequence:

f(n)=32(1.5)n=48n

Now you can find your first four terms (assuming first term start when n=1)

First term: f(1)=48(1)=48

Second Term: f(2)-48(2)=96

Third Term: f(3)=48(3)=144

Forth Term: f(4)=48(4)=196