
Jon S. answered 09/01/20
Patient and Knowledgeable Math and English Tutor
The number of squares is increasing by 4 each time, so this is an arithmetic sequence where the first term, a(1), is 4 and the common difference (d) is 4.
The explicit formula is a(n) = a(1) + (n-1)*d
a(n) = 4 + (n-1)*4
a(n) = 4 + 4n -4
a(n) = 4n