Mark M. answered 09/01/20
Mathematics Teacher - NCLB Highly Qualified
If by "zero term" you mean which term is zero, then
0 = 128 - (n - 1)(32)
0 = 128 - (32n - 32)
0 = 128 - 32n + 32
0 = 160 - 32n
32n = 160
n = 5
Or
128, 96, 64, 32, 0
Liz R.
asked 09/01/20For the arithmetic sequence below determine the common difference and write the explicit rule and zero term
Mark M. answered 09/01/20
Mathematics Teacher - NCLB Highly Qualified
If by "zero term" you mean which term is zero, then
0 = 128 - (n - 1)(32)
0 = 128 - (32n - 32)
0 = 128 - 32n + 32
0 = 160 - 32n
32n = 160
n = 5
Or
128, 96, 64, 32, 0
Alex E. answered 09/01/20
I’ve assisted hundreds of repeat students over the past ten years
The zeroth term in the sequence is the first term in the sequence....128.
The explicit rule of the sequence is developed by the pattern in the sequence.... so if the pattern is decreasing by 32. Then the explicit rule of the sequence {an} given is.... an+1 = an - 32.
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