
Victoria V. answered 08/18/20
20+ years teaching Algebra 2 subjects & beyond.
Please see video. :-)
Mai W.
asked 08/18/20Find three consecutive integers such that five times the sum of the first and -4 is 35 less than the sum of the second and third.
Victoria V. answered 08/18/20
20+ years teaching Algebra 2 subjects & beyond.
Please see video. :-)
Let's call the first integer N, the second N+1, and the third N+2
The sum of the first integer and -4 is N - 4.
The sum of the second and third integer is N+1 + N+2 = 2N + 3
We are also told that the sum of the first integer and -4 (which is N - 4) is 35 less than the sum of the second and third integer (which is 2N + 3) ; or putting it in math expressions:
N - 4 = 2N + 3 - 35. ; simplfy and solve for N: 28 = N
So the first integer is 28, the second is 29 and the third is 30
CHECK:
28 - 4 = 24
29 + 30 = 59 indeed 24 is 35 less than 59.
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Bud L.
08/19/20