Write an equation in slope- intercept form for the line with slope -1/3 and y-intercept 9.

Answer 1

This is a good question. There are a few ways we could tackle this, but the easiest way is to use the equation y=mx+b

where m is the slope of the graph (meaning how it "slants") and b is the y intercept meaning where the line crosses the y axis.

If the slope of the line is -1/3, then we plug that in for m

and if the y intercept is 9, we plug that in for b.

So we get y=(-1/3)x+9

Answer 2

Slope Intercept Form is y = mx + b where m is the slope and b is the y intercept when x = 0

For m= -1/3

y intercept = 9 = b

y intercept has the coordinates (0, 9)

y = -1/3(x) + 9