David F. answered 07/30/20
Math Wiz from MIT
N = 2850√(100-x).
1. using this model, how many (N) of the 28520 babies will survive to age 5?
Substitute x = 5
2850*SQRT(100-5) = 27,778.4 = 27.778 babies (need to round to the nearest integer)
2. What is the practical domain of this function?
This is asking what values can x take on. The minimum value of anyone is x = 0 at birth
The maximum value of 100-x that keeps a non-negative value is x = 100.
The domain of x is [0,100]
3, When only 5,000 of this group are still alive, how old (x) do you expect them to be?
5000 = 2850 * SQRT(100-x)
(5000/2850)^2 = 100-x
x = 100 - (5000/2850)^2 = 97 years old
4. after how many years (x) will half the original population of 28,520 people (N=14,260) remain alive?
14260 = 2850 * SQRT(100-x)
x = 100 - (14260/2850)^2 = 25 years