Please I need a detailed answer to this question written out how you got answer

Question

The distance a spring stretcher varies directly with the weight of the object hung on the spring. If a 20 pound weight stretches a spring 8 inches how far will a 50 pound weight stretch this spring.

Answer 1

Hi AMY!!!

D = kW where D is the distance the spring stretches, W is the weight of the object attached to the spring, and k is the fixed proportionality constant.

8 = 20k <--- 8 inch stretch with 20 lb weight

8/20 = k

2/5 = k

So D = (2/5)W

For W=50, the stretch distance shall be D = (2/5)(50) = 20