Raymond B. answered 10/25/20
Math, microeconomics or criminal justice
Profit P = R-C = 75x - x^2/2 - 35x -300 = -x^2/2 + 40x -300
take the derivative of the profit function and set it equal to zero for maximum profit
P' = -x + 40 = 0, x= 40
P(40) = -(40)^2/2 + 40(40) -300 = 800-300 = 500 < 2500. $2500 isn't possible
for P=50 = -x^2/2 + 40x -300
-x^2/2 +40x -250 =0
x^2 -80x + 500 = 0
x^2 -80x + 1600 = 1600-500 = 1100
(x-40)^2 = 11(100)
x-40 = 10sqr11
x = 40 + or - 10sqr11 = 73.2 or 6.8