
Mitiku D. answered 02/10/15
Tutor
4.9
(205)
Electrical Engineer, Patient and Objective
squeeze theorem lim x->0 (sin x / x) = 1.
(tan(x))/x <=> sin(x))/xcos(x) <=> [(sin(x))/x]*1/cos(x)
The value of the term in [] is one and cos(x) can be evaluated by just substituting zero for x.
Answer:lim x->0 (tan(x))/x = 1
I hope this helps