a feasible region has vertices at (0,0), (30), (3/2,7/2), and (0,3). what are the maximum and minimum values for the objective function P=6x+8y?

Question

which one is the answer?

a) minimum (0,0)=0

maximum (3/2,7/2) =37

b) minimum (0,0)=0

maximum (3,0) =24

c) minimum (0,0)=14

maximum (3/2,7/2) =17

d) minimum (0,0)=0

maximum (0,3) =30

Answer 1

Hello Marwa,

Simply substitute all four point (x and y) values into the p equation for x and y and see which points get you the highest and lowest p-values and what they are. Then match it to the correct choice.