How much energy (in J) is lost when a sample of iron with a mass of 26.0 g cools from 76.0 °C to 23.0 °C?

Question

Express your answer with the appropriate units

Answer 1

The specific heat of iron is .45 joules per °C per kg, or .45 j °C^-1 g^-1

 

The change is temperature is 53 degrees, and the mass is 26 g.

 

So you need to calculate:

 

.45  j / °C - g  *  53 °C  *  26 g = 620.1 joules