1) To solve this the bases must be the same so rewrite 4 as 2^2 which gives us 2^2(2x) = 2^x-6 which means that 2(2x) must = x-6
4x = x-6 3x=-6 X=-2
2) Need to change this from log form to exponential form which gives us 5^3 = 6x-1
125= 6x -1. 6x=126. X= 21
3) The only way I see to rewrite this is (2x^3 )(5y^-1) or 10x^3y^-1
Stephen K.
06/22/20
Allie B.
Could u explain how u got question 3?06/22/20