
Kayla K.
asked 06/12/20Slope of 3/2 and passing through the point (- 2, 5)
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1 Expert Answer

Nitin P. answered 06/12/20
Tutor
4.9
(134)
Machine Learning Engineer - UC Berkeley CS+Math Grad
Given the slope of a line and a point (a,b) on it, you can immediately construct the equation from the point-slope form:
y = m(x - a) + b
In this case, we have:
y = 3/2(x + 2) + 5 = 3x/2 + 8
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Lisa A.
You can write your line in point slope form or slope intercept form. For point slope form which is y-y1 = m(x-x1) m is your slope and your point (-2,5) is your x1, y1 so your equation would be y-5 = 3/2 (x+2) since x - -2 becomes x+2. If you want slope intercept form which is y=mx+b, you can plug in 5 for y, 3/2 for m, and -2 for x so you would have 5 = 3/2(-2) + b to find the y intercept 5 = 3/2*-2/1 + b 5 = -3 + b and add 3 to both sides so b = 8 So your slope intercept equation would be y = 3/2x + 806/12/20