admission to a baseball game is $2.00 for general admission and $3.50 for reserved seats. the receipts were $2716.00 for 1139 paid admissions. how many of each ticket were sold?

Answer 1

Let G be the number of general seats sold.

Let R be the number of reserved seats sold.

The total number of seats sold is G + R = 1139

Since general seats costs $2 each, 2G is the total receipts from general tickets sales.

Since reserve seats costs $3.50 each, 3.5R is the total receipts from reserved ticket sales.

The total receipts is 2G + 3.5R = 2716

We now have two equations in two unknowns and can solve for G and R.

Answer 2

Hi Brandon. You can assign $2 to x, and $3.50 to (1139 - x). When you combine x with 1139 - x, you get 1139 total tickets.

So 2x + 3.50 (1139 - x) = $2,716. By distributing, we get 2x + 3986.50 - 3.50x = 2716.

Getting “x only” to one side, and “numbers only” to the other, we get

-1.50x = -1270.50. Dividing both sides by -1.50, we get x = 847, the number of $2 tickets.

To find the number of $3.50 tickets, we take 1139 - 847 = 292 tickets.