Samuel P. answered 06/07/20
Former high school math teacher. Currently working in finance at Big 4
Since you want the probability of BOTH events (not just 1, and not AT LEAST 1) you find the probability of EACH event happening, then multiply them together.
P(heads)= 1/2
P(rolling a 4) = 1/6
P(Heads & rolling a 4) = (1/2)*(1/6)= (1/12)
I hope this helps!
Best,
Sam