Sin (theta)^2 + cos(theta)^2 = 1
so 0.982^2 + cos(theta)^2 = 1
0.964 + cos(theta)^2 = 1
cos(theta)^2 = 0.036
cos(theta) = 0.189 (in 1st quadrant and -0.189 in 2nd quadrant)
Katherine A.
asked 06/03/20Sin (theta)^2 + cos(theta)^2 = 1
so 0.982^2 + cos(theta)^2 = 1
0.964 + cos(theta)^2 = 1
cos(theta)^2 = 0.036
cos(theta) = 0.189 (in 1st quadrant and -0.189 in 2nd quadrant)
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