I do I set this up, and solve?

Question

Find the equation of the line in point slope form passing through (-6,2) and perpendicular to -5x+6y=18

Answer 1

The point slope form of a line equation is (y-y₁) = m(x-x₁)

Here the line equation is -5x+6y=18.

The slope of the given line is 5/6

Any line perpendicular to this line should have a slope of -6/5 to satisfy m₁m₂ = -1.

So the slope of the new line is -6/5

SO the equation of the new line in point slope form is

(y-2) = (-6/5)(x+6)