Mark M. answered 05/31/20
Retired college math professor. Extensive tutoring experience.
If you multiply the "top" and "bottom" by a2b2, you will get:
(2b2 - 2a2) / (3b2 + 3a2)
Brian P.
asked 05/30/202 2
--- - ----
a^2 b^2
------------------------- LCM=a^2b^2 If I multiply numerator >>> 2a^2 2a^2 2b^2 2b^2
3 3 ------ - ------ + ------- - -------
--- + ------ a^2 b^2 a^2 b^2
a^2 b^2
Is this correct at this point or did I improperly distribute?
Mark M. answered 05/31/20
Retired college math professor. Extensive tutoring experience.
If you multiply the "top" and "bottom" by a2b2, you will get:
(2b2 - 2a2) / (3b2 + 3a2)
Sam Z. answered 05/30/20
Math/Science Tutor
Cancel a^2*b^2=(2-2)/(3+3)=0
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.