First combine the 2 fractions in the numerator which gives you (x+y)/xy
Now divide this by the fraction in the denominator which gives you
(x+y) (3) / (x+y) (xy)
The (x+y) in numerator and denominator cancel out leaving 3/(xy)
Brian P.
asked 05/30/20I appreciate the help that I have received on this topic, and though am still struggling, I am determined to get a grasp of this concept. Is the LCM in this problem 3xy, and if so how would you distribute that in this problem?
1 1
--- + ----
x y
---------------------
x+y
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3
First combine the 2 fractions in the numerator which gives you (x+y)/xy
Now divide this by the fraction in the denominator which gives you
(x+y) (3) / (x+y) (xy)
The (x+y) in numerator and denominator cancel out leaving 3/(xy)
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