
Kathleen B. answered 05/28/20
University of Virginia Undergrad with Knowledge in Multiple Subjects
For this problem, you need to understand the 68-95-99.7 rule. This states that in a normal distribution, 68% of the data is within 1 standard deviation of the mean, 95% is within 2 standard deviations, and 99.7% is within 3 standard deviations. I suggest you look up a picture of this to visualize what this looks like on a curve.
72 is one standard deviation from the mean, and 90 is 2 standard deviations from the mean. Since 68% of the data is within one standard deviation, this covers 72 to 84. To get the remaining range of 84-90, you need to find the percentile of a score of 90. Divide 95% by 2 to get 47.5, and add this to 50% to find that the percentile is 97.5. The percentile of 72, on the other hand is 50 - 68%/2, or 16. So the total percentage in this range is 97.5-16, or 81.5.
If 19 students scored between a 72 and a 90, and this should represent 81.5% of the data, you can set up a ratio and solve for x.
19/x = 81.5/100
81.5x = 1900
x = 23 people took the test