Sum of an arithmetic sequence = n/2 * (2a + (n-1)d), where n = number of terms, a = first term, d = common difference between terms.
Here n = 51, a = -282 and d = 16. Plug those numbers into the formula and you have your answer.
Mallory P.
asked 05/26/20What is the sum of the first 51 terms of the sequence?
-282, -266, -250, -234....
S51=
Sum of an arithmetic sequence = n/2 * (2a + (n-1)d), where n = number of terms, a = first term, d = common difference between terms.
Here n = 51, a = -282 and d = 16. Plug those numbers into the formula and you have your answer.
Yefim S. answered 05/26/20
Math Tutor with Experience
This is arithmetic sequense with a1 = - 282 and common difference d = - 266 - (- 282) = 16.
Then a51 = a1 + 50d = - 282 + 50·16 = 518.
Then S51 = 51/2(a1 + a51) = 51/2(- 282 + 518) = 6018
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