
Al P. answered 05/22/20
Online Mathematics tutor
The number of ways of choosing r items from a population of n, where order matters, is : nPr = n!/(n-r)!
24P3 = 24!/(24-3)! = 24*23*22 = 12144
Without using the permutation formula, we can reason this out: there are 24 choices for the first student selection, 23 for the 2nd, and 22 for the 3rd, giving you 24*23*22 different orderings, as we saw with the formula.
[ When order does not matter, then the selection is nCr = n!/ ((n-r)!r!). One example where you may see this: How many 5-card poker hands have exactly one pair? Because the order in which they are dealt does not matter, there is that extra division of r! to remove the overcounted combinations. ]