Bereket G. answered 05/20/20
I love to see the success of people.
8000=5000(1+r)^6
Then we solve for r
1.08=1+r
r=0.08
Alyssa N.
asked 05/20/20What interest rate to the nearest percent is needed to grow 5,000 to 8,000 in 5 years if interest is compounded annually?
Bereket G. answered 05/20/20
I love to see the success of people.
8000=5000(1+r)^6
Then we solve for r
1.08=1+r
r=0.08
Taylor D. answered 05/20/20
Experienced Tutor Specializing in Math and Engineering
Use the Compound Interest Formula to solve for the interest rate:
A = P(1+r/n)nt
Where
A = The final amount
P = The initial amount
r = Rate
n = number of times compounded per year
t = time in years
Just fill in the formula with the known values and solve for the unknown value(r):
8000 = 5000(1+r/1)1*5
Divide r by 1 and Multiply 5 by 1:
8000 = 5000(1+r)5
Divide both sides of the equation by 5000:
1.6 = (1+r)5
Get rid of the exponent by taking the fifth root of both sides of the equation:
1.0985 = 1+r
Subtract 1 from both sides of the equation:
0.0985 = r
Now multiply r by 100 to turn the rate from a decimal to a percent:
r = 9.85%
The Correct Answer is: 9.85%
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