Write the first six terms of the sequence: a(1) = 2 a(n) = a(n-1) -4

Question

a) 1, 2, 3, 4, 5, 6

b) 0, 1, 2, 3, 4, 5

c) 2, -2, -6, -10, -14, -18

d) 2, -8, 32, -128, 512, -2,048

Answer 1

recursive is a(n)=a(n-1)+d

a(n)=a(n-1)-4

a(1)=2 and d=-4

so, explicit formula is a(n)=a(1)+(n-1)d

a(1)=2+(1-1)(-4)=2

a(2)=2+(2-1)(-4)=2-4=-2

a(3)=2+(3-1)(-4)=2-8=-6

a(4)=2+(4-1)(-4)=2-12=-10

a(5)=2+(5-1)(-4)=2-16=-14

a(6)=2+(6-1)(-4)=2-20=-18

c) is the answer