recursive rule in sequences

Question

if f(0)=3

f(n)=4f(n-1)

what are the first 6 terms

Answer 1

The first six terms are:

f(0) = 3

f(1) = 4·f(0) = 4·3 = 12

f(2) = 4·f(1) = 4·12 = 48

f(3) = 4·f(2) = 4·48 = 192

f(4) = 4·f(3) = ?

f(5) = ?

You finish f(4) and f(5). Note that each term is 4 times the previous term, which is what the recursive rule is telling us.