Finding the Zeros of f

Question

Find the zeros of f(x) = 2x^2 + 32.

The zeros of f are x=? and x=?

Answer 1

The zeros occur when f(x) = 0, so set f(x) = 0 and solve for x:

0 = 2x² + 32

0 = 2(x² + 16)

0 = x² + 16 [divided both sides by 2]

-16 = x²

√(-16) = x

±4i = x