x0 = 1
x1 = f(x0) = f(1) = 3(1) + 5 = 3 + 5 = 8
x2 = f(x1) = f(8) = 3(8) + 5 = 24 + 5 = 29
x3 = f(x2) = f(29) = 3(29) + 5 = 87 + 5 = 92
Mia J.
asked 05/13/20Find the third iterate. x3 of the function f(x)=3x+5 for an inital value of x0=1
x0 = 1
x1 = f(x0) = f(1) = 3(1) + 5 = 3 + 5 = 8
x2 = f(x1) = f(8) = 3(8) + 5 = 24 + 5 = 29
x3 = f(x2) = f(29) = 3(29) + 5 = 87 + 5 = 92
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