(S+2)T=63
(S-2)T=51
63/(S+2) = 51/(S-2)
63S-126=51S+102
12S=228
S=19 mph
Mia J.
asked 05/13/20The wind added 2 mph to Jaime’s rate when she was rowing with the wind and subtracted 2 mph from her rate on her return trip. Jaime found that in the same amount of time she could row 63 miles with the wind, she could go only 51 miles against the wind.
(S+2)T=63
(S-2)T=51
63/(S+2) = 51/(S-2)
63S-126=51S+102
12S=228
S=19 mph
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Mia J.
thank you !05/13/20