A parabola with is vertex at (22, 20) and its axis of symmetry parallel to the y-axis passes through the point (2, 260). Write an equation of the parabola. Then find the value of y when x=32.

Question

A parabola with is vertex at (22, 20) and its axis of symmetry parallel to the y-axis passes through the point (2, 260). Write an equation of the parabola. Then find the value of y when x=32.

Answer 1

y=a(x-h)^2+k

y=a(x-22)^2+20

260=a(2-22)^2+20

260=a(-20)^2+20

240=a(400

a=240/400

a=3/5

y=(3/5)(x-22)^2+20

y=(3/5)(32-22)^2+20

y=(3/5)(10)^2+20

y=(3/5)(100)+20

y=60+20

y=80