
Christopher J. answered 05/12/20
Berkeley Grad Math Tutor (algebra to calculus)
The specific term of a binomial expansion (a+b)n is given by the following formula
(n n-r)*ar *bn-r where (n n-r) is equal to n! / (r!*(n-r)!) ! is factorial symbol.
We are considering (3q-s)15
So a=3q and b=-s
We are looking for term q2s13 so in this case we use n=15, r=2, a=3q, b=-s
By the formula, we get 15!/(2!*(13)!)*(3q)2 * (-s) 13
remember (3q)2 = 9q2 (-s)13 = -s13
See what you get when you multiply all terms together!