(r.s)(x)=(3x2)+2
(r+s)(x)=(x+2)+(3x2)
(r-s)(x)=(x+2)-(3x2) ⇒ (r-s)(-1)=(-1+2)-(3*(-1)2)=1-3=-2
Xavier D.
asked 05/11/20Suppose the function r and s are defined for all real numbers x as follows
r(x)=x+2
s(x)=3x^2
write the expressions for (r.s)(x) and (r+s)(x) and evaluate (r-s)(-1)
(r.s)(x)=
(r+s)(x)=
(r-s)(-1)=
(r.s)(x)=(3x2)+2
(r+s)(x)=(x+2)+(3x2)
(r-s)(x)=(x+2)-(3x2) ⇒ (r-s)(-1)=(-1+2)-(3*(-1)2)=1-3=-2
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