
Mark M. answered 05/10/20
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
0 = cos θ
θ ∈ {90°, 270°}
0 = cos (θ - 17º)
90° = θ - 17°
107° = θ
270º = θ - 17°
287° = θ
Mark M. answered 05/10/20
Mathematics Teacher - NCLB Highly Qualified
0 = cos θ
θ ∈ {90°, 270°}
0 = cos (θ - 17º)
90° = θ - 17°
107° = θ
270º = θ - 17°
287° = θ
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