Sam Z. answered • 05/08/20
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4.3
(12)
Math/Science Tutor
log[log(4+log2(x+1))]=0 for x
(x+1)^.5=-4
see, log0=1
so log1=0
Mare T.
asked • 05/08/20Solve the equation log[log(4+log2(x+1))]=0 for x
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2 Answers By Expert Tutors
Mark M. answered • 05/08/20
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5.0
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Mathematics Teacher - NCLB Highly Qualified
log [log (4 + log 2(x + 1))] = 0
log (4 + log 2(x + 1)) = 1
10 = 4 + log 2(x + 1)
6 = log 2(x + 1)
106 = 2(x + 1)
1000000 = 2(x + 1)
500000 = x + 1
499999 = x
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