
Arturo O. answered 05/08/20
Experienced Physics Teacher for Physics Tutoring
I think you meant to say "of multiplicity 2."
f(x) = A(x - 0)(x - 3)2 = Ax(x - 3)2
24 = A(4)(4 - 3)2
24 = 4A
A = 6
f(x) = 6x(x - 3)2
Renee M.
asked 05/08/20find a polynomial function f(x) of degree 3 with real coefficients that satisfies the following conditions zero of 0 and zero of 3 multiplying 2 ; f(4)=24
Arturo O. answered 05/08/20
Experienced Physics Teacher for Physics Tutoring
I think you meant to say "of multiplicity 2."
f(x) = A(x - 0)(x - 3)2 = Ax(x - 3)2
24 = A(4)(4 - 3)2
24 = 4A
A = 6
f(x) = 6x(x - 3)2
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