for f(x) = x^2 -9 the x intercept is where y = 0 so x^2 -9 =0 x = +3 and -3
y intercept is where x =0 so y=-9
for f(x)/3 x intercept is at (x^2 -9 ) = 0 x= +3 and -3
y intercept is (0-9)/3 =y y=-3
Anna T.
asked 05/07/20f(x)= x^2-9
g(x)= 1/3f(x)
for f(x) = x^2 -9 the x intercept is where y = 0 so x^2 -9 =0 x = +3 and -3
y intercept is where x =0 so y=-9
for f(x)/3 x intercept is at (x^2 -9 ) = 0 x= +3 and -3
y intercept is (0-9)/3 =y y=-3
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