Nelli D. answered 05/13/20
Love learning and teaching everything about Math
a) A=Pert
given r=0.0353 and P(initial population)=6.14
A=6.14e0.0353t
b)from 2012 to 2018 our t=6
A=6.14e0.0353(6)=7.59 million
c) final population 9 million means our A=9
9=6.14e0.0353t (solving for t)
9/6.14=e0.0353t
ln(9/6.14)=ln(e0.0353t)
0.3824=0.0353t (log property applied)
0.3824/0.0353=t
t=10.8 approximately in 11 years the population will be 9million
d)A=6.14e0.0353t (doubling time is referring to doubled population, A=2x6.14)
12.28=6.14e0.0353t
2=e0.0353t
ln(2)=ln(e0.0353t)
ln(2)=0.0353t
ln(2)/0.0353=t
t=19.6 approximately 20 years is out doubling time (if asked to round to the nearest year, if not then keep the decimal value)