Patrick B. answered • 21d

Math and computer tutor/teacher

Generally speaking LN( x1 * x2 * ... * xN ) = LN(x1) + LN(x2) + .... + LN(xN)

so you got ln(3) + ln(A) + ln(b) + ln(5) + ln(c)

Jackson S.

asked • 22dThe problem I am struggling with is:

ln(3ab*5c) .

I've reviewed all my notes and am still struggling. Any help would be appreciated!

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Patrick B. answered • 21d

Math and computer tutor/teacher

Generally speaking LN( x1 * x2 * ... * xN ) = LN(x1) + LN(x2) + .... + LN(xN)

so you got ln(3) + ln(A) + ln(b) + ln(5) + ln(c)

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