I assume that what you mean by this is to work out the derivative of the tangent starting from the difference quotient
d (tan(x))/dx = lim [tan(x + h) - tan(x) ]/ h { limit as h → 0 }
When this is worked out using the angle addition formula for tangent :
tan( x + h) = [ tan(x) + tan(h) / [ 1 - tan(x) tan(h) ]]
It is found that the result is indeed sec2 (x) provided that
lim tan(h) / h = 1. { limit as h →0 }
This is the case. It follows from lim sin(h) / h = 1
This latter limit cannot be proven by purely algebraic methods. The proof is from geometry. It involves the approach of a regular n-gon to circle as n → ∞