How to solve (x+1)^2(x-4)

Question

Could I have a detailed explanation on how to solve (x+1)^2(x-4)

Thank you!

Answer 1

The question is incomplete. I assume you want to solve for x in

(x + 1)²(x - 4) = 0

Set each factor equal to zero.

(x + 1) = 0

x = -1

Since the factor (x + 1) appears twice, -1 is a root of multiplicity 2. Similarly,

(x - 4) = 0

x = 4

The factor (x - 4) appears once, so 4 is a root of multiplicity 1.