Given cotA=1160 and that angle A is in Quadrant I, find the exact value of cscA in simplest radical form using a rational denominator.

Answer 1

cotA=11/60

tan=opposite/adjacent

cot=1/tan

cot=adjacent/opposite

cotA=11/60

adjacent=11

opposite=60

using the Pythagorean Theorem, the hypotenuse=61

csc=1/sin

cscA=1/sinA

sin=opposite/hypotenuse

sinA=60/61

csc=1/sin

cscA=61/60