Joseph B. answered 04/28/20
Experienced SAT, Algebra, Geometry, Trig and Pre-Calculus tutor
x-value | y-value | |
Starting point: (-16,2) | -16 | 2 |
x-intercept: (-12,0) | -12 | 0 |
y-intercept: (0,-2) | 0 | -2 |
Additional point | 20 | -4 |
To find starting point: Note that you can't have a negative number less than 0 under the sqrt sign. So, the smallest number x could be is -16. When you plug -16 in for x, you get 2 for y.
To find x intercept, let y (or f(x)) = 0. If you do that, you can an x of -12.
To find y intercept, let x = 0. When you do, you get y (i.e. f(x)) of = -2.
For the additional point, plug in 20 for x, and you get a y (i.e. f(x)) of -4.